Question

find the height of a trapezium whose area is 65 sq.cm and the length of the parallel sides are 13cm and 26 cm.

Answer 1

Let the height be H cm.

Area of trapezium = 65
=> (a+b) *H /2 = 65
=> (13+26) H = 130
=> 39 H = 130
=> H = 10/3
=> H = 3.3 cm

Answer 2

area of trapezium=1/2(sum of sides)×height
65 =1/2(39)×height
65×2. =39× height
130. =39× height
130/39=height
3.3. =height

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