Question

find the height of a trapezium whose area is 68cm square and whose bases are 13 and26cm​

Answer 1

Answer :-

$area \: of \: trapezium \: = 68 \: {cm}^{2} \\ 1 \div 2(sum \: of \: parallelsides) \: \times height = 68 \: {cm}^{2} \\ 1 \div 2(13 + 26) \times h \: =68 \\ 1 \div 2\times39 \times h \: = 68 \\ h \: = 68 \times 2 \div 39 \\ h = 3.48m$

So, Answer = 3.48 m (approx)

Hope it helps you!