Question

Find the height of a tree,if it casts a shadow 17m long on the level of ground,when the angle of elevation of the sun is 45 degree.

Answer 1

angle= 45degree

shadow=17m

tanA=P/B

so,

tan 45 =h/17

h = 17m

so, the hieght is 17m

Answer 2

Height of tree is 17 m.

Given:

• A tree casts a shadow 17m long on the level of ground,
• When the angle of elevation of the sun is 45°.

To find:

• Find the height of tree.

Solution:

Concept to be used:

• Draw the figure.
• Apply trigonometric ratio to find the height.

Step 1:

Draw the figure according to the statement.

See the attachment.

Let AB is tree.

It's shadow is AC.

Step 2:

Apply tan trigonometric ratio.

$tan \: C = \frac{AB}{AC}$

or

$tan \: 45^{\circ} = \frac{AB}{17}$

or

$\frac{AB}{17} = 1$

or

$\bf \pink{AB = 17 \: m}$

Thus,

Height of tree is 17 m.

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