Question

find the height of a triangle whose area is x3-6x2 +11x and base is 2x
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Answer 1

Answer:

$area \: \: \: of \: \: \: a \: \: \: triangle \: \: \: = \frac{1}{2} \times b \times h \\ \\ {x}^{3} - 6 {x}^{2} + 11x = \frac{1}{2} \times 2x \times h \\ \\ \frac{ {x}^{3} - 6 {x}^{2} + 11x }{2x} \times 2 = h \\ \\ \frac{x( {x}^{2} - 6x + 11) \times 2 }{2x} = h \\ \\ {x}^{2} - 6x + 11 = h$

Answer 2

Answer:

Area of triangle = 1/2 *b*h

x cube -6x square + 11x =1/2*2x*h

x cube - 6x square +11x /2x. *2 = h

x square - 6x + 11 = h