Question

Find the height of a triangle whose base is 40cm and area is 0.04 sq m.

Answer 1

Answer:

20 cm

Step-by-step explanation:

base=40 cm=0.4 m

area=0.04m=1/2*b*h

=1/2*0.4*h

=0.2*h

⇒h=0.2m=20 cm

Answer 2

$\huge\mathbb{\underline{SOLUTION:-}}$

$\sf\underline{\underline{\red{GIVEN:-}}}$

Height of triangle ?

base =$\sf \frac{40}{100}=0.4m$

and area $\sf=0.04m{}^{2}$

$\sf\underline{\underline{\red{According\: to\: Question :-}}}$

we know that the area of triangle:-

$\sf \frac{1}{2}×base×height$

Now we have to find the height of triangle

$\sf\implies \frac{1}{2}×0.4×h=0.04\\ \sf\implies \ 0.2×h=0.04\\ \sf\implies h= \frac{0.04}{0.2}\\ \sf\implies multiply\: with 100 to\: remove \: the \: point \\ \sf h=\frac{0.04}{0.2}×\frac{100}{100}\\ \sf\implies h=\frac{4}{20}\\ \sf\implies h=\frac{\cancel4}{\cancel20}\\ \sf\implies Height= \frac{1}{5}=0.002$

The height of triangle =0.2m

$\sf\boxed{\underline{\red{Height=0.2m}}}$

Height = 0.2

base =0.4

area =$\sf 0.04 m{}^{2}$

$\sf \frac{1}{2}×base×height$

$\sf Area\:of\: triangle= \frac{1}{2}×base×height\\ \sf\implies 0.04 = \frac{1}{2}×0.2×0.4\\ \sf\implies 0.04 =0.2×0.2\\ \sf\implies 0.04=0.04\\ \sf L.H.S=R.H.S$

Hence proved ! ! !