find the height of an equilateral triangle whose side is 2 centimetre
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the height of an equilateral triangle is also its median
hence, base gets divided into 2 equal parts
Therefore,
Base = 1cm
Hypotenuse = 2cm
h^2 = b^2 + p^2
2^2 = 1^2 + p^2
4 = 1 + p^2
p^2 = 4 - 1
p^2 = 3
p = 3^(1/2)
Hence, the height of the ∆ is 3^(1/2) cm
hence, base gets divided into 2 equal parts
Therefore,
Base = 1cm
Hypotenuse = 2cm
h^2 = b^2 + p^2
2^2 = 1^2 + p^2
4 = 1 + p^2
p^2 = 4 - 1
p^2 = 3
p = 3^(1/2)
Hence, the height of the ∆ is 3^(1/2) cm
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