Question

Find the height of an isosceles triangle each of whose equal side measures 45 cm and base is 72 cm. Also find its area.​

Answer 1

Answer:

Height = 27 cm

Area = 972 Sq cm

Step-by-step explanation:

Height of Isosceles triangle = $\sqrt{45^{2} - 36^{2} }$ = 27

Area = 1/2 * 72 * 27 = 972 Sq cm