Find the height of an Isosceles triangle whose each of the equal side measure 45cm and the base is 72cm.And find its area.
Answers
Answered by
5
let the height be h
b= base
a= equal sides
so height (h) = √(a² - b²/4)
h = √(45² - 72²/4 )
h = 27 cm
area of triangle = 1/2 x h x b = 1/2 x 27 x 27 = 972 cm²
ANSWER
So the height = 27 cm and area = 972 cm²
b= base
a= equal sides
so height (h) = √(a² - b²/4)
h = √(45² - 72²/4 )
h = 27 cm
area of triangle = 1/2 x h x b = 1/2 x 27 x 27 = 972 cm²
ANSWER
So the height = 27 cm and area = 972 cm²
Attachments:
Elysium:
can you make it less complicated?? Its right but i did not understand how you did it
have it helped now??
thank you
thank you sooooooo much :D
have u understand the thing ??
kinda but will do........thanks again
welcome
Answered by
2
let hight be = h
base=b
area=a
height=(45square - 72square/4)
height=27cm
area=1/2*27*27=972square
base=b
area=a
height=(45square - 72square/4)
height=27cm
area=1/2*27*27=972square
Similar questions