Find the height of cylinder whose r is 7cm and tsa is 968cm sq
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15cm
tsa=2*pi*r(h+r)
968=2*22/7*7(h+7)
22=h+7
h=22-7
h=15cm
Answered by
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Answer:
15 cm
Step-by-step explanation:
Given that ,
Radius of the cylinder ( r ) = 7 cm
And cross section area of the cylinder = 968 square cm
Let the height of the cylinder = h cm
We know that,
Cross section area of cylinder
= 2 * π * r ( h + r )
Then,
968 = 2 * 22/7 * 7 (h+7)
h + 7 = 968 / 44
h + 7 = 22
h = 22-7
h = 15 cm
Hence the height of cylinder is equal to 15 cm.
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