Math, asked by Janvi2596, 1 year ago

Find the height of cylinder whose r is 7cm and tsa is 968cm sq

Answers

Answered by mahekv2003
0

15cm

tsa=2*pi*r(h+r)

968=2*22/7*7(h+7)

22=h+7

h=22-7

h=15cm

Answered by PravinRatta
2

Answer:

15 cm

Step-by-step explanation:

Given that ,

Radius of the cylinder ( r ) = 7 cm

And cross section area of the cylinder = 968 square cm

Let the height of the cylinder = h cm

We know that,

Cross section area of cylinder

= 2 * π  * r ( h + r )

Then,

968 = 2 * 22/7 * 7 (h+7)

h + 7 = 968 / 44

h + 7 = 22

h = 22-7

h = 15 cm

Hence the height of cylinder is equal to 15 cm.

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