Math, asked by Anonymous, 10 months ago

find the height of equilateral triangle whose side is the 15 cm​

Answers

Answered by saketranjan91
0

Step-by-step explanation:

area =225×3^1/2/4

225×3^1/2/4=1/2 ×15×h

h=15×3^1/2/2

Answered by Anonymous
19

Step-by-step explanation:

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area =  \frac{ \sqrt{3} }{4} {a}^{2}  \\  \\  =   \frac{ \sqrt{3} }{4}  \times 15 \times 15 \\  \\  \frac{225 \sqrt{3} }{4}  \:  \:  \:  {cm}^{2}  \\  \\ area \: of \: triangle =  \frac{1}{2}  \times b \times h \\  \\  \frac{225 \sqrt{3} }{4}  =  \frac{1}{2}  \\  \\   = \frac{1}{2}  \times base \:  \times height \\  \\ \frac {225 \sqrt{3}}{4} {cm}^{2}  =  \frac{1}{2}  \times 15 \times height \\  \\ height \:  = \frac {51.96}{4} \\  \\ height \:  = 13 {cm}

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