Question

find the height of on a object reached in the time taken by 2sec(g=10m/s​

Answer 1

given:-

g = a = 10 m/s

t = 2 sec

s (height) = ?

explaination:-

as wkt, s = ut + 1/2 at^2

....

s = (0) 2 + 1/2 (10) (2)^2

hence by equating the above sum we will get

s (height) = 20 meters.

HOPE IT HELP'S YOU..