find the height of rhombus if the length of diagonal are 8 and 6 cm
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Step-by-step explanation:
If length of two diagonals of a rhombus are x and y respectively.
Then length of the side = √ [(x/2)^2 + (y/2)^2]
In given question length of two diagonals are 6 cm and 8 cm respectively.
Length of the side = √ [ (6/2)^2 + (8/2)^2]= √ [3^2 + 4^2] = √ [ 9+16 ] = √25 = 5 cm
Hence length of the side is 5 cm
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If length of two diagonals of a rhombus are x and y respectively.
Then length of the side = √ [(x/2)^2 + (y/2)^2]
In given question length of two diagonals are 6 cm and 8 cm respectively.
Length of the side = √ [ (6/2)^2 + (8/2)^2]= √ [3^2 + 4^2] = √ [ 9+16 ] = √25 = 5 cm
Hence length of the side is 5 cm.
Then length of the side = √ [(x/2)^2 + (y/2)^2]
In given question length of two diagonals are 6 cm and 8 cm respectively.
Length of the side = √ [ (6/2)^2 + (8/2)^2]= √ [3^2 + 4^2] = √ [ 9+16 ] = √25 = 5 cm
Hence length of the side is 5 cm.
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