Question

Find the height of the cylinder whose volume is 1.54m3 and diameter of the base is 0.7m

Answer 1

Given :-

• Volume of cylinder = 1.54 m³
• Diameter of cylinder = 0.7 m
• Radius of cylinder = 0.7/2

To find :-

• Height of cylinder

Solution :-

As we know that

Volume of cylinder = πr²h

Let the height be h

→ 1.54 = 22/7 × 0.7/2 × 0.7/2 × h

→ 1.54 = 11 × 0.1 × 0.7/2 × h

→ 1.54 = 0.77/2 × h

→ 1.54 × 2 = 0.77h

→ 3.08 = 0.77h

→ h = 3.08/0.77

→ h = 7 cm

Hence,

• Height of cylinder is 7 cm

Extra Information

• Area of rectangle = length × breadth
• Area of square = side × side
• Perimeter of square = 4 × side
• Perimeter of rectangle = 2(length + breadth)
• Area of rhombus = ½ × product of diagonals
• Area of Parallelogram = base × height
• Area of trapezium = ½ × sum of parallel sides × height

Answer 2

Given ,

• Volume of cylinder = 1.54 m³
• Diameter of cylinder = 0.7 m

We know that ,

Diameter = 2 × Radius

Thus ,

Radius = 0.7/2 m

Now , the volume of cylinder is given by

$\boxed{ \sf{Volume = \pi {(r)}^{2}h }}$

Thus ,

$\sf \mapsto 1.54 = \frac{22}{7} \times \frac{0.7}{2} \times \frac{0.7}{2} \times h \\ \\ \sf \mapsto 1.54 \times \frac{0.77}{2} \\ \\ \sf \mapsto h = \frac{3.08}{0.77} \\ \\ \sf \mapsto h = 4 \: \: m$

$\sf \therefore{ \underline{ {The \: height \: of \: cylinder \: is \: 4 \: m}}}$