Question

find the height of the cylinder whose volume is 1.54m³ and diameter of the base is 14cm? ​

Answer 1

Given :

Volume of cylinder = 1.54m³

Diameter of base = 14 cm

To find :

Height of cylinder.

Solution :

Diameter of cylinder base = 14 cm

∴ Radius of cylinder = 14/2 = 7 cm = 0.07m

∵ Volume of cylinder = πr²h

Now atq,

⇒ 1.54 = 22/7 × (0.07)² × h

⇒ 1.54 = 22/7 × 0.0049 × h

⇒ 1.54 = 0.0154 × h

⇒ h = 1.54/0.0154

⇒ h = 100 m

∴ Height of cylinder = 100 m.

Answer 2

Answer:

Given :-

• A cylinder whose volume is 1.54 m³ and diameter is 14 cm.

To Find :-

• What is the height of the cylinder.

Formula Used :-

${\red{\boxed{\large{\bold{Volume\: of\: cylinder\: =\: {\pi}{r}^{2}h}}}}}$

where,

• r = Radius
• h = Height

Solution :-

First, we have to find the radius,

As we know that,

★ $\sf Radius =\: \dfrac{Diameter}{2}$ ★

Then,

⇒ $\sf Radius =\: \dfrac{14}{2}$

➠ $\sf\bold{\green{Radius =\: 7\: cm}}$

Now, we have to change cm to m,

As we know that,

✯ 1 cm = 100 m ✯

Then,

↪ 1 cm = 100 m

↪ 7 cm = $\sf\dfrac{7}{100}$

➤ Radius = 0.07 m

Given :

• Volume = 1.54 m³
• Radius = 0.07 m

According to the question by using the formula we get,

↦ $\sf 1.54 =\: \dfrac{22}{7} \times {(0.07)}^{2} \times h$

↦ $\sf 1.54 =\: \dfrac{22}{7} \times 0.0049 \times h$

↦ $\sf 1.54 =\: 0.0154 \times h$

↦ $\sf \dfrac{1.54}{0.0154} =\: h$

➦ $\small\bf{\underbrace{\red{h =\: 100\: m}}}$

$\therefore$ The height of the cylinder is 100 m .