Question

Find the height of the cylinder whose volume is 4928 cm³ and diameter of the base is 28 cm? steps pls

Answer 1

$\large \sf \: hi \: \: buddy$

$\large \sf \star \: \underline{ solution : }$

Given :

• Volume = 4928 cm³
• Diameter = 28cm

To Find :

• Height

$\\ \large \sf \star \: \underline{ \underline{formula : }}$

$\large \sf \looparrowright \underline{ \boxed{ \sf \: volume = \pi {r}^{2} h}}$

• r = Radius
• h = height

$\\ \large \tt \mapsto \: radius = \frac{diameter}{2} \\ \\ \large \sf \: radius = 14cm \\ \\ \large \tt \leadsto \: \pi = \frac{22}{7}$

Solving :

$\\ \large \tt : \implies \: 4928c {m}^{3} = \frac{22}{7} \times 14 \times 14 \times h \\ \\ \\ \large \tt : \implies \: 4928c {m}^{3} = \frac{22}{ \cancel7} \times \cancel{ 14} \: \: 2 \times 14 \times h \\ \\ \\ \large \tt : \implies \: 4928c {m}^{3} = {22}\times 2 \times 14 \times h \\ \\ \large \tt : \implies \: 4928c {m}^{3} = 616 \times h \\ \\ \\ \large \sf \star \: \: on \: \: transposing \: \: terms : \\ \\ \large \tt : \implies \: h = \frac{4928c {m}^{ 3} }{616}$

Height = 8cm