Question

Find the height of the cylinder whose volume is
$1.54 {m}^{3}$
and diameter of the base is 140cm?

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Answer 1

Answer:

A/q,

Radius of base = 70 cm

Volume of cylinder = 1.54 m³

i.e

$volume = \pi {r}^{2} h \\ \frac{22}{7} \times \frac{70}{100} \times \frac{70}{100} \times h = \frac{154}{100} \\ h = \frac{154 \times 100 \times 7}{22 \times 70 \times 70} = 1 \: \: m$

Height is 1 m.

Ans.

Answer 2

Volume of cylinder = 1.54 m ³

and diameter of cylinder = 140 cm

Radius (r) = $\frac{d}{2}=\frac{140}{2}$=70 cm

Volume of cylinder = πr²h

$⇒ 1.54 = \frac{22}{7} \times 0.7 \times 0.7 \times h$

After simplifying, we get the value of h that is

$h = \frac{1.54 \times 7}{22 \times 0.7 \times 0.7}$

$⇒ h = 1$

Hence, height of the cylinder is 1 m.