find the height of the hall whose length is 4m which and which can be covered by 2400 tiles of size 25cm by 20cm
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Answer:
let the height be h.
length=4m=400cm
area of wall=400*h cm²
area of tile=25*20=500cm²
therefore no. of tiles required=2400
∴400*h/500=2400
⇒h= 2400*500/400
=3000cm=30m
length=30m
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