Question

Find the height of the parallelogram whose area and base are 368 sq cm and the 23 cm respectively

Answer 1

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Area of parallelogram = 368 sq. cm

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• Base of parallelogram = 23 cm

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• The height of the parallelogram

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• Let the height of parallelogram be "h"

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$\underline{\bold{\texttt{Area of parallelogram :}}}$

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➠ Base × Height

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$\underline{\bold{\texttt{Area of given parallelogram :}}}$

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• Area = 368 sq. cm.

• Base = 23 cm.

• Height = h

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So,

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➜ 368 = 23 × h

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➜ $\sf h = \dfrac { 368 } { 23 }$

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➨ h = 16

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Hence the height of parallelogram is 16 cm

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Aᴅᴅɪᴛɪᴏɴᴀʟ ɪɴғᴏʀᴍᴀᴛɪᴏɴ

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Perimeter of parallelogram

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• 2(a + b)

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Where,

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➻ a = Side

➻ b = Base

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• Opposite sides are congruent

• Opposite angels are congruent

• Consecutive angles are supplementary

• If one angle is right, then all angles are right

• The diagonals of a parallelogram bisect each other

• Each diagonal of a parallelogram separates it into two congruent triangles

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