Question

Find the height of the poles. Two men on either side of a temple of 50 metres height observe its top at the angles of elevation of 30° and 60° respectively. Find the distance between the two men.​

Answer 1

Step-by-step explanation:

Hope so it will help

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Answer 2

$\sqrt{3}$Answer:200/$\sqrt{3}$ metre

Step-by-step explanation:

lets suppose that the first men sitting on the left side of the temple see its top at an angle of elevation of 30 degree. then the height of the pole will be 50 metre according to question .

the tan 30 degree = perpendicular/base

tan 30 degree = 1/$\sqrt{3}$

perpendicular = 50 metre

1/$\sqrt{3}$ = 50/B

B = 50$\sqrt{3}$

THEN  suppose that the second men sitting on the right side of the temple see its top at an angle of elevation of 60 degree. then the height of the pole will be 50 metre according to question .

the tan 30 degree = perpendicular/base

tan 60 degree = $\sqrt{3}$

perpendicular = 50 metre

$\sqrt{3}$ = 50/B

B = 50/$\sqrt{3}$

sum of both distance = distance between them = 50$\sqrt{3}$ + 50/$\sqrt{3}$

                                                                               = 200/$\sqrt{3}$ metre

hope it helps you!!