Question

Find the height of the projectile 4 seconds after it is launched (t=4)
a) 80.2 m
b) 81.2 m
c) 81.8 m
d) 84 m

Answer 1

Answer:

option a

Step-by-step explanation:

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Answer 2

c) 81.8 m

Given:

The time of flight=4s

Now, as per the formula,

2usinθ / g = 4

or usinθ= 4/2g

usinθ= 2g

Now, assuming h is the height of the projectile, then

h = (usinθ)4− 1/2 g (4)²

h = 2g ×4− 1/2 g×16

= 8.34g

= 81.8 m           (since the value of g is 9.8m/sec²)

Hence, the height of the projectile 4s after it is launched will be 81.8 m