Question

find the height of the projectile 4 secs after it's launched(t=4)
a) 80.2m
b) 81.2m
c) 81.8m
d) 84m​

Answer 1

Answer:

Step-by-step explanation:

Correct option is

A

98m

Time of flight=4+5=9 s

so,  

g

2usinθ

​

=9

or usinθ=  

2

9g

​

 

if h is the height of P, then

h=(usinθ)4−  

2

1

​

g(4)  

2

 

=  

2

9g

​

×4−  

2

1

​

g×16