Math, asked by manujaiswal19800, 8 months ago

find the height of the trapezium in which parallel sides are 2 5cm and 10 cm and non parallel sides are 14cm and 14cm

Attachments:

Answers

Answered by aniruddha786
0

Answer:

I don't know

Step-by-step explanation:

sorry but

area of trapezium = 1/2*(sum of parallel base)

*height

Answered by Selisho
1

Answer:

√159.75 centimetres.

  • Divide the trapezium into a rectangle and a triangle.
  • The dimensions of the square will be 14cm x 2.5cm.
  • The length of the hypotenuse of the triangle is given as 14cm.
  • The base length is (10cm - 2.5cm) = 7.5cm.
  • Therefore the height of the trapezium between the two parallel sides can be calculated using Pythagoras' theorem: (14 x 14 cm^2 - 7.5 x 7.5 cm^2)
  • Which is equivalent to 196 sq. cm - 56.25 sq. cm.
  • Then find the square root of 159.75.

Similar questions