find the height of the trapezium in which parallel sides are 2 5cm and 10 cm and non parallel sides are 14cm and 14cm
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0
Answer:
I don't know
Step-by-step explanation:
sorry but
area of trapezium = 1/2*(sum of parallel base)
*height
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1
Answer:
√159.75 centimetres.
- Divide the trapezium into a rectangle and a triangle.
- The dimensions of the square will be 14cm x 2.5cm.
- The length of the hypotenuse of the triangle is given as 14cm.
- The base length is (10cm - 2.5cm) = 7.5cm.
- Therefore the height of the trapezium between the two parallel sides can be calculated using Pythagoras' theorem: (14 x 14 cm^2 - 7.5 x 7.5 cm^2)
- Which is equivalent to 196 sq. cm - 56.25 sq. cm.
- Then find the square root of 159.75.
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