Question

find the height of the trapezium the sum of lengths of whose base is 50 cm and whose area is 500 CM square

Answer 1

Area of trapezium is given by:
½(sum of the two parallel sides)x height

so,
½x 50 x h = 500
h= 20 cm

answered :-)

Answer 2

Hey Bro.

This is your answer ....


Sum of parallel sides = 50 cm.
Given Area = 500 cm². 
Here, h = height , a and b are two parallel sides.
$Also, area of trapezium = \frac{1}{2} X h X (a+b)$
$500 = \frac{1}{2} hX(a+b) \\ \\ 500= \frac{1}{2}hX50 \\ \\ \frac{500}{50}= \frac{1}{2} h \\ \\ h= 20$
Hence height of trapezium is 20 cm.

Hope it helps