Question

Find the height of the tree shown
in the given figure .
free

a loom
b) 159am
c 115m
d] 144 m​

Answer 1

Answer:

115m

Let BC= h be the height of the tree.

Given :

Theta = 30°

AB = 200m

In ∆ABC,

$\large \: tan 30 = \frac{BC}{AB} = \frac{h}{200} </p><p></p><p>$

We know that tan 30 = 1/√3 ,

$\large \frac{1}{ \sqrt{3} } = \frac{h}{200}$

Cross multiplying,

$\large \: h = \frac{200}{ \sqrt{3} }$

Rationalising the denominator,

$\large \: h \: = \frac{200}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{200 \sqrt{3} }{3}$

$\large \: h \: = \frac{ 200 \times 1.73}{3}$

$\large \: h = \frac{346}{3} = 115.3m$