Question

Find the height of the triangle Whose area is 168 Cm sq and whose base is 16 Cm

Answer 1

Answer:

Given:

The area of the triangle $168cm^2$ and the base of the triangle $16cm$.

To find the height of the triangle, by using the formula of area of the triangle.

Step by step solution:

Step 1 of 2: Note the formulas

We know the formula of the area of the triangle is $\frac{1}{2} \times h \times b$

where $h=$ the height of the triangle and $b=$ the base of the triangle

Step 2 of 2: Substituting the values and we get

Substituting the values of area and base of the triangle and we get

$168= \frac{1}{2} \times h \times 16\\\Rightarrow h= \frac{168 \times 2}{16}\\\Rightarrow h = \frac{336}{16}\\\Rightarrow h= 21$

Therefore, the required height of the triangle is $21cm$.

Answer 2

Concept:

The region occupied inside the perimeter of a flat object or figure is referred to as "area." The total space occupied by the three sides of a triangle is called its area.

Given:

The area of the triangle $=168cm^2$.

The base of the triangle $=16 cm^2$.

Find:

Find the height of the triangle.

Solution:

The area of a triangle is defined as the entire area contained by a triangle's three sides. In a nutshell, it's half of the base multiplied by the height.

Area of triangle $=\frac{1}{2} *b*h$

where b and h are the base and height of the triangle.

$Area=\frac{1}{2}*b*h$

$h=\frac{2*Area}{b}$

$h=\frac{2*168}{16}$

$h=21cm$

Hence the height of the triangle is $21cm.$