Question

find the height of the triangle whose area is equal to 56 dM square base is equal to 2.8 m

Answer 1

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Answer 2

The height of the triangle is 2 dm

Step-by-step explanation:

Base of triangle = 2.8 m

1 m = 10 dm

2.8 m = 28 dm

So, Base of triangle = 2.8 m

Area of triangle =$\frac{1}{2} \times Base \times Height$

Area of triangle =$\frac{1}{2} \times 28 \times Height$

We are given that area of triangle is 56 dM square

So, $\frac{1}{2} \times 28 \times Height = 56$

Height =$\frac{56 \times 2}{2 \times 28}$

Height = 2

Hence the height of the triangle is 2 dm

#Learn more:

Find the height of the triangle whose:

(i) area = 28.9 m², base = 8.5 m

(ii) area = 56 dm², base = 2.8 m

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