Question

Find the height of the wall whose length is 4 m and which can be covered by 2400 tiles of size 25 cm by 20 cm

Answer 1

Area of tile= 25×20 cm^2 = 500cm^2
So, area of 2400 tiles= 2400×500cm^2
=1200000cm^2 = 1200000÷10000 m^2
= 120 m^2
Let height be h,
Then area of wall= 4hm^2
-> Area of the wall = area of 2400tiles
-> 4h=120
-> 4h÷4 = 120÷4 = 30m (Ans)


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