find the height of the wall whose length is 4cm and which can be covered by 2400tiles of size 25cm by 20cm
Answers
Answered by
2
hey here is your answer
Area of tile= 25×20 cm^2
= 500cm^2
So, area of 2400 tiles
= 2400×500cm^2
=1200000cm^2
=1200000÷10000 m^2
= 120 m^2
Let height be h,
Then area of wall
= 4hm^2
-> Area of the wall
= area of 2400tiles
-> 4h=
=120
-> 4h÷4
= 120÷4
30m (Ans)
Area of tile= 25×20 cm^2
= 500cm^2
So, area of 2400 tiles
= 2400×500cm^2
=1200000cm^2
=1200000÷10000 m^2
= 120 m^2
Let height be h,
Then area of wall
= 4hm^2
-> Area of the wall
= area of 2400tiles
-> 4h=
=120
-> 4h÷4
= 120÷4
30m (Ans)
sweetandsimple64:
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Answered by
0
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