Math, asked by benjamin5244, 1 year ago

find the height of the wall whose length is 4cm and which can be covered by 2400tiles of size 25cm by 20cm

Answers

Answered by sweetandsimple64
2
hey here is your answer

Area of tile= 25×20 cm^2

= 500cm^2

So, area of 2400 tiles

= 2400×500cm^2


=1200000cm^2


=1200000÷10000 m^2


= 120 m^2


Let height be h,


Then area of wall

= 4hm^2


-> Area of the wall

= area of 2400tiles


-> 4h=

=120


-> 4h÷4

= 120÷4

30m (Ans)

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Answered by prudhvi149
0
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