Question

find the height of the ∆whose base and area are 3 cm and 10.5 square cm​

Answer 1

Answer:

area of the traingle

$\large{1/2XbaseXhieght}$

$\large{10.5cmsq=1/2X3cmXhieght}$

$\large{10.5X2/3=hieght}$

$\large{hieght=7cm}$