Question

find the height of Trapezium the sum of length of whose bases as 39cm and whose area is 65 CM square





find the surface area of a cube whose edge is 11cm​

Answer 1

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$\frak {\underline {\dag \; \; Question : 1}}$

• Find the height of Trapezium the sum of length of whose bases as 39cm and whose area is 65 cm².

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$\frak {\underline {\dag \; \; Given :}}$

• Area of trapezium = 65 cm²
• Sum of length of bases = 39 cm.

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$\frak {\underline {\dag \; \; To \; find :}}$

• Height of trapezium

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$\frak {\underline {\dag \; \; Formula :}}$

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$\boxed {\sf { Area \; of \; trapezium \; = \dfrac {1}{2} \times {sum\; of \; parallel \; sides} \times h}}$

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$\frak {\underline {\dag \; \; Solution :}}$

$\implies \sf { 65 = \dfrac{39}{2} \times h}$

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$\implies \sf { 65 \times \dfrac {2}{39} = h }$

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$\implies \sf { \dfrac{130}{39} = h}$

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$\implies \sf {3.33 = h}$

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Therefore, the height of trapezium = 3.33 cm.

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$\frak {\underline { \dag \; \; Question : 2 }}$

• Find the surface area of cube whose one edge is 11 cm.

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$\frak {\underline { \dag \; \; Given :}}$

• Edge of cube = 11 cm

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$\frak {\underline {\dag \; \; To \; find :}}$

• Surface area of cube

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$\frak {\underline {\dag \; \; Formula :}}$

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$\boxed {\sf {T.S.A \; of \; cube = 6(side)^2}}$

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$\frak {\underline {\dag \; \; Solution :}}$

$\implies \sf { T.S.A = 6(11)^2}$

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$\implies \sf { T.S.A =6(121)}$

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$\implies \sf { T.S.A = 726}$

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Therefore, T.S.A of cube = 726 cm².

Answer 2

Question 1 :

• Find the height of Trapezium the sum of length of whose sum of parallel sides is 39cm and whose area is 65cm².

Given :

• Area of Trapezium = 65cm²
• Sum of parallel sides (a + b) = 39cm

To Find :

• Height of the Trapezium

Solution :

We know that,

⠀⠀⠀⠀⠀★ Area = ½ × (a + b) × height

⟶⠀Area = ½ × (a + b) × height

⟶⠀65 = ½ × 39 × height

⟶⠀65 × 2 = 39 × height

⟶⠀130 = 39 × height

⟶⠀130/39 = height

⟶⠀3.33 = height⠀⠀⠀⠀⠀[approx]

So, Height of the Trapezium is 3.33cm

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Question 2 :

• Find the surface area of a cube whose edge is 11cm.

Given :

• Shape = Cube
• Side of Cube = 11cm

To Find :

• Total Surface Area (TSA)

Solution :

We know that,

⠀⠀⠀⠀★ Total Surface Area = 6(side)²

⟶⠀Total Surface Area = 6 × (side)²

⟶⠀Total Surface Area = 6 × (11)²

⟶⠀Total Surface Area = 6 × 11 × 11

⟶⠀Total Surface Area = 6 × 121

⟶⠀Total Surface Area = 726cm²

So, Total Surface Area of Cube is 726cm²

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