Question

Find the height of trapezium whose area is 112 sq. cm and sum of parallel side is 14cm

Answer 1

Answer:

Given,

Area of trapezium=112m^2

Sum of parallel sides=14cm

we know that,

Area of trapezium=1/2×sum of its parallel sides ×height

Let,

height of trapezium be 'h'

According to question,

112=1/2×14×h

h=112×7

h=16m

Hence,

Height of the trapezium=16m

Hope it helps you.

#follow me and Mark as brainlist plz....

Answer 2

Answer:

Hence, value of height of the trapezium will be 16 cm

Step-by-step explanation:

In context to question asked,

We have to determine the one parallel side of trapezium

As per question,

It is given that,

Area of trapezium = 112 sq. cm.

Sum of parallel sides = 14 cm

As we know that,

Area of trapezium

$A = \frac{a+b}{2}\times h\\Where,\:A = Area\\a,b = Parallel\:sides\:of\:trapezium\\h =Height$

So, for determining the value of height of trapezium,

We will put the value given in question in above formula,

Thus we will get,

$A = \frac{a+b}{2}\times h\\112= \frac{14}{2}\times h\\=>h = \frac{112}{7}\\=>h = 16\:cm$