find the HFC of following by method of prime factoriation 27,63 18,48
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H.C.F by prime factorisation is in the attachment. Here I write only factors.. ...
H.C.F. of (18, 48) = 2 x 3 = 6. ...
H.C.F. of (30, 42) = 2 x 3 = 6. ...
H.C.F. of (18, 60) = 2 x 3 = 6. ...
H.C.F. of (27, 63) = 3 x 3 = 9. ...
H.C.F. of (36, 84) = 2 x 2 x 3 = 12. ...
H.C.F. of (34, 102) = 2 x 17 = 34. ...
(h) Factors of 91 = 7 x 13.
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