find the highest angle of rhombus PQRS in which altitude from P to side RS bisects RS is
Answers
Highest angle of rhombus PQRS = 120° in which altitude from P to side RS bisects RS
Step-by-step explanation:
Let say PM ⊥ RS bisects RS
=> RM = SM = RS/2
PQRS is rhombus
=> PQ = QR = RS = PS
Comparing Δ PMS & Δ PMR
PM = PM (common)
SM = RM
∠PMS = ∠PMR = 90°
=> Δ PMS ≅ Δ PMR
=> PS = PR
=> PQ = QR = PR = RS = PS
Hence ΔPQR & ΔPRS are Equilateral Triangle
=> ∠PQR = ∠PSR = 60°
∠QPS = ∠QPR + ∠QPS = 60° + 60° = 120°
∠QRS = ∠QRP + ∠SRP = 60° + 60° = 120°
Highest angle of rhombus PQRS = 120° in which altitude from P to side RS bisects RS
Learn more:
PQRS is a square and PQTU is a rhombus. Angle UPS =136degree ...
https://brainly.in/question/12860463
in a rhombus if one angle is 120°,find all remaining angle - Brainly.in
https://brainly.in/question/13181142
BY bisects angle b of triangle ABC. Prove that BZYX is a rhombus ...
https://brainly.in/question/13770065