find the highest common factor of 72 and 1452
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hcf of 72 and 1452
by prime factorising,
72 = 2^3 * 3^2
1452= 2^2 * 3 * 11^2
therefore HCF = 2^2 * 3 = 12
by prime factorising,
72 = 2^3 * 3^2
1452= 2^2 * 3 * 11^2
therefore HCF = 2^2 * 3 = 12
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