Question

find the highest number by which 101 and 137 can be divided so as leave remainder 5 in each case

Answer 1

To find the largest number which divides 101 and 137 leaving remainder 5 in each case i.e. HCF.

Consider HCF be x.

In order to make 101 and 137 completely divisible by x, we need to deduct the remainder 6 from both the cases.

101-5=96
137-5=132

Hcf of 96 and 132 = 12

∴ largest number which divides 101 and 137 leaving remainder 5 in each case is 12.

Answer 2

Answer:

answer is 12

answer is 12