find the highest number by which 101 and 137 can be divided so as leave remainder 5 in each case
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To find the largest number which divides 101 and 137 leaving remainder 5 in each case i.e. HCF.
Consider HCF be x.
In order to make 101 and 137 completely divisible by x, we need to deduct the remainder 6 from both the cases.
101-5=96
137-5=132
Hcf of 96 and 132 = 12
∴ largest number which divides 101 and 137 leaving remainder 5 in each case is 12.
Consider HCF be x.
In order to make 101 and 137 completely divisible by x, we need to deduct the remainder 6 from both the cases.
101-5=96
137-5=132
Hcf of 96 and 132 = 12
∴ largest number which divides 101 and 137 leaving remainder 5 in each case is 12.
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8
Answer:
answer is 12
answer is 12
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