find the hight of a rectangle box of length 8 cm, width 6cm, where the length of diagonal is 11 cm.
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Answer:
Hight =√21cm
Step-by-step explanation:
Diagonal line on the 2d plane of rectangular box = √(6^2+ 8^2)=10cm
then hight of the rectangular box=√(11^2 -10^2) =√21 cm
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