Question

Find the hole cube of
(3.2)​

Answer 1

$(3.2)^3 = (3 + 0.2)^3\\\\(a+b)^3 = a^3 + b^3 + 3ab (a+b)\\\\here \ , \ a = 3 \ , b = 0.2\\\\(3 + 0.2)^3 = 3^3 + (0.2) ^3 + 3 * 3 * 0.2 (3 + 0.2)\\\\(3 + 0.2)^3 = 9 + 0.8 + 1.8 ( 3 + 0.2)\\\\(3 + 0.2)^3 = 9 + 0.8 + 5.4 + 0.36\\\\(3 + 0.2)^3 = 15.56\\\\hope \ it \ helps \ !!$