Question

find the horizontal force required to move a body waiting 200 kg on a rough horizontal surface having coefficient of friction 0.35 take G is equals to 10 metre per second square ​

Answer 1

Answer:

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

f=μN=μmg=0.5×10×10=50N

So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

−2

Answer 2

$\Huge\bf\maltese{\underline{\pink{Question ࿐}}}\maltese$

Find the horizontal force required to move a body waiting 200 kg on a rough horizontal surface having coefficient of friction 0.35 take G is equals to 10 metre per second square.

$\Huge{\textbf{\textsf{{\purple{Ans}}{\pink{wer}}{\color{}{:}}}}}$

The force required to move the body is 686 N.

$\huge{\color{t}{\textsf{\textbf {\underline{\underline{ Explanation : }}}}}}$

• Mass of the body = 200 kg
• Coefficient of friction = 0.35

• Force required to move the body = ??

$\bigstar \: \boxed{\sf{F = \mu N}}★$

$\sf{N = {m \times g}}N=m×g$ So, replacing it in the formula, it forms,

$\sf{F =\mu \times \: m \times g}$

muμ = 0.35

m = 200 kg

g = 9.8 m/s²

$\longrightarrow{\sf{F = 0.35 \times 200 \times 9.8}}$

$\longrightarrow{\sf{F = 70 \times 9.8}}$

$\longrightarrow{\sf{F = 686 \: N}}$

Force required = 686 N

Therefore, the force required to move the body is 686 N.