find the horse power of the engine required to lift 1 ton of coal per minute from a mine of 60m deep
Answers
Answer:
Mass(m) = 100000 kg = 10^5 kg
Height (h) = 360m
Acceleration due to gravity = 10 m/s^2
Time(t) = 1 hour = 3600 s
Then,
P.E = mgh
= 10^5 * 10 * 360 J
Work done = P.E = 10^5 * 10 * 360 J
We know,
Power = Work done / Time
= 10^5 x 10 x 360/3600
= 10^5 watt.
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Explanation:
Answer:
The horse power of engine is 166 Watt
Explanation:
- The power an engine produces is referred to as "horsepower."
- It is determined by the amount of force required to move 550 pounds one foot in a second or 33,000 pounds one foot in a minute.
- 0.9863 horsepower or 4,500 kilogram-metres per minute is the metric horsepower.
Given,
Mass() = 1 ton = 1000 kg =
Height () = 60
Acceleration due to gravity =
Time(t) = 1 hour = 3600 s
Then,
= × 10 × 60
Work done = P.E = × 10 × 60
We know,
= x 10 x 60/3600
= 166 Watt
Therefore, the horse power of engine is Watt
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