Question

Find the hybridisation for SO2 , CO3^-2 and PO4^-3​

Answer 1

Explanation:

No. of valence electrons in central atom. (carbon)= 4

Extra electrons in CO3^-2 = 2

Total electrons in central atom = 6

Hybrid oribitals required = 6/2 = 3

Hybridization = sp2

Geometry = trigonal

Answer 2

$\underline{\red{\rm Hybridisation :- }}$

• When two or more atomic orbitals of nearly same energy Intermix to form same number of new orbitals of exactly same energy , the orbits are called hybrid orbitals and the process is called Hybridisation .
• It is done for central atom .
• By hybridisation sigma bond is formed .

$\rule{200}2$

$\underline{\red{\rm We\ know\ that :- }}$

$\boxed{\sf Hyb. =\dfrac{1}{2}\bigg[ valance \ e^-_{on \ central\ atom } + Number_{monovalent\ atom} \pm Charge \bigg] }$

$\underline{\red{\rm For \ SO_2:- }}$

$\sf\longrightarrow Hyb. = \dfrac{1}{2} ( 6 + 0 + 0 ) = 3 \\\\\bf\longrightarrow Hyb. = sp^2$

$\underline{\red{\rm For \ CO_3^{-2}:- }}$

$\sf\longrightarrow Hyb. = \dfrac{1}{2} ( 4 + 0 + 2 ) = 3 \\\\\bf\longrightarrow Hyb. = sp^2$

$\underline{\red{\rm For \ PO_4^{-3}:- }}$

$\sf\longrightarrow Hyb. = \dfrac{1}{2} ( 5 + 0 + 3 ) = 3 \\\\\bf\longrightarrow Hyb. = sp^3$