Question

Find the hypotenuse of a right angled triangle with height 12dm and base 16dm

Answer 1

${h}^{2} = {b}^{2} + {p}^{2}$

${h}^{2} = {16}^{2} + {12}^{2}$

${h}^{2} = 256 + 144$

${h}^{2} = 400$

$h \: = \sqrt{400}$

$h = \sqrt{20 \times 20}$

$h = 20$

$so \: hypotenuse \: = 20dm$

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