Question

Find the hypotenuse of a right triangle whose sides containing right angle are 10 cm and 24 cm the answer is 26 m what is the solution?

Answer 1

Step-by-step explanation:

by pythagoras theorm

hypotenuse ² = perpendicular ² + base²

= under root 10²+ 24²

= under root 100+ 576

= under root 676 = 26cm

Answer 2

26cm

Given perpendicular and base 10cm and 24cm

To find the hypotenuse use pythagoras theorem

$(hypotenuese)^{2} = (perpendicular)^{2} + (base)^{2}$

= $10^{2} + 24^{2}$  

= 100 +576

$(hypo)^{2}$=676

hypo = $\sqrt{676}$  = 26

so the hypotenuese is 26 cm