Question

find the hypotenuse of a triangle whose base is 10m and perpendicular is 11m​

Answer 1

Answer:

$\sqrt{221}$

Step-by-step explanation:

By using Pythagoras theorem,

${H }^{2} = { B}^{2} + {P}^{2}$

${H}^{2} = {10}^{2} + {11}^{2}$

${H}^{2} = 100 + 121$

$H = \sqrt{221}$