Question

find the hypotenuse of right angled triangle if its sides are 10 and x​

Answer 1

Step-by-step explanation:

• H=√100+x2
• ₹^^₹;_+₹-:_*:

Answer 2

Answer:

in ∆ABC

AB=10, BC=X and AC=?

in∆ABC by Pythagoras therom

AC²=AB²+BC²

AC²=10²+x²

AC²=100+x²

AC=√100+x²

AC=10+x

AC=X+10

so the hypotenuse of right ∆ABC be X+10