Question

find the hypotenuse of the right angle
triangle whose perpendicular sides
are√2and√1​

Answer 1

Step-by-step explanation:

• (p) ^2+(b) ^2=(h) ^2
• (√2)^2+(√1)^2=(h)^2
• 2+1=h^2
• 3=h^2
• h=√3 (ans)

Answer 2

let the triangle be ABC, such that AB is hypotenuse,BC and AC are two perpendicular sides..

Now, applying Pythagoras theorem,

AC²=AB²+BC²

AC²=(√2)² + (√1)²

AC²= 2 + 1

AC² = 3

AC = √3 .

Hope it will help you.. I'm new on brainly..

thanks for giving me chance to answer..