Question

find the hypotenuse of the right angled triangle whose sides are 40 cm 9 CM​

Answer 1

Step-by-step explanation:

please see the above attachment

Answer 2

Correct Question-:

• Find the hypotenuse of the right angled triangle whose sides are 40 cm and 9 cm .

AnswEr-:

• $\underline{\boxed{\star{\sf{\purple{Hypotenuse \:of\:Right\:Angled\:Triangle\:is\:41cm}}}}}$

Explanation-:

$\frak{Given-:\:}\begin{cases} & \sf{ The\: right\: angled\: triangle\: whose \;sides\: are\: 40 \:cm \:and\: 9 \:cm .} \end{cases}$

$\frak{To\:Find\:-:}\begin{cases} & \sf{ The\: Hypotenuse \:of\:right\: angled\: triangle\: .} \end{cases}$

By Analysing Attachment -:

• ABC is a Right Angled Triangle.
• $\frak{In\:Triangle \:ABC\:-:}\begin{cases} & \sf{ BC = Base = 9cm .} & \\\\ \sf{AB\: = \: Perpendicular \:40cm} & \\\\ \sf{ AC \: = Hypotenuse= ??}\end{cases}$

Now ,

• $\underline{\boxed{\star{\sf{\purple{Pythagoras \: Theorem \: =Hypotenuse ² = Base² + Perpendicular²}}}}}$

Here ,

• Hypotenuse = ??
• Base = 9 cm
• Perpendicular = 40 cm

Now ,

• $\implies{\sf{\large {Hypotenuse² = 40² + 9² }}}$
• $\implies{\sf{\large {Hypotenuse² = 1600 + 9² }}}$
• $\implies{\sf{\large {Hypotenuse² = 1600 + 81 }}}$
• $\implies{\sf{\large {Hypotenuse² = 1681 }}}$
• $\implies{\sf{\large {Hypotenuse = \sqrt{1681}}}}$
• $\implies{\sf{\large {Hypotenuse = 41 cm }}}$

Therefore,

• $\underline{\boxed{\star{\sf{\purple{Hypotenuse \:of\:Right\:Angled\:Triangle\:is\:41cm}}}}}$

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