Math, asked by shivanjalim8a, 7 months ago

Find the hypotnuse of a right angled triangle whose other two sides are 12 cm 5cm

Answers

Answered by ayushrajsingh2431

Step-by-step explanation:

$h {}^{2} = p { }^{2} + b {}^{2}$

h²= 12²+5²

h²=144+25

h²=169

h=√169=√13×13

h=13

hence,

the hypotnuse of a right angled triangle whose other two sides are 12 cm 5cm= 13

Answered by mehak238517

The Pythagorean theorem will give the answer for any pair of values of the two sides. If the two input values are integers, in most cases the result will not be an integer because you’re taking the square root of an integer.

However, there are special cases, known as Pythagorean triples, where all three values (2 inputs and 1 result) will be integers. You just happened to pick one of them: 5, 12, 13. Another triple is 3, 4, 5.

I’m betting that anyone who answered this question or contemplated answering it would have recognized that 5, 12 are part of a Pythagorean triple and would have known the answer (13) without having to do the calculation.

For extra credit, do some research on triples and see what patterns they form. You’ll find it interesting.

Ansss.....Let x be the length of the hypotenuse. Then from the Pythagorean theorem we take: 5^2 + 12^2 = x^2 => x^2 = 169 => x = 13

Therefore, the length of the hypotenuse is 13 cm. The triple (5, 12, 13) is the second primitive Pythagorean triple.

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