Find the identities of
1) (8.9)^2
2) 297*303
Answers
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3
1) (8.9)^2
(9-0.1)^2
(9)^2-2(9)(0.1)+(0.1)^2
81-1.8+0.01
81-17.9
79.2
2) (297)(303)
=(300−3)(300+3)
Using ,
(a−b)(a+b)=a^2^ −b^2
we get,
(300)^2 −(3)^2
=90000−9
=89991
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