Question

Find the image, nature, position and linear magnification when an object is placed in 12cm from a concave lens with f=-10cm

Answer 1

Answer:

Here, focal length of concave lens, f=−15cm.

object distance, u=?, image distance, v=−10cm, magnification of lens, m=?

As 1f=1v/−1u,1u=1v/−1f=1−10+115=−130oru=−30cm

Thus the object should be placed at a distance of 30 cm on the left side of the concave lens.

Linear magnification, m=vu=−10−30=13.

The positive sign of m shows that the image is virtual and erect, and its size is (1/3) of the size of the object

Explanation:

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