Find the image of a point (2, 3) with respect to the
radi-cal axis of two circles x
2
+ y2
+ 8x + 2y + 10 =
0 and x
2 + y2 – 2x – y – 8 = 0.
Answers
Answered by
0
Step-by-step explanation:
Q 1
[2]2+[3]2+8[2]+2[3]+10=0
4+6+16+6+10=0
20+22=0
42=0
Q 2
[2]2+[3]2-2[2]-[3]-8=0
4+6-4-3-8=0
10-4-11=0
10-15=0
5=0
Similar questions